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Write an equation in slope intercept form of a line that passes through the points (-6, 14) and (5, -41).

User Manu P
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Final answer:

The equation of the line in slope-intercept form that passes through the points (-6, 14) and (5, -41) is y = -5x -16.

Step-by-step explanation:

To write an equation in slope-intercept form of a line that passes through the points (-6, 14) and (5, -41), we need to find the slope (m) and the y-intercept (b).

The formula to find the slope is:

m = (y2 - y1) / (x2 - x1)

Substituting the given points, we get:

m = (-41 - 14) / (5 - (-6))

m = (-55)/(11) = -5

Now, we can use one of the given points and the slope to find the y-intercept:

y = mx + b

Using (-6, 14), we get:

14 = -5(-6) + b

14 = 30 + b

b = 14 - 30

b = -16

Therefore, the equation of the line in slope-intercept form is:

y = -5x -16

User Jpuntd
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