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A-2÷3 ≤ 2a ± 3÷5±5÷8

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Answer:

To solve the given inequality, let's break it down step by step:

a - 2/3 ≤ 2a ± 3/5 ± 5/8

First, simplify the expressions on both sides of the inequality:

a - 2/3 ≤ 2a ± 3/5 ± 5/8

Let's start with the right side:

2a ± 3/5 ± 5/8

To simplify this, we need a common denominator. The least common multiple of 5 and 8 is 40, so:

2a ± (3/5) ± (5/8) = (16a ± 24 ± 25)/40

Now we can rewrite the inequality:

a - 2/3 ≤ (16a ± 24 ± 25)/40

Next, let's get rid of the fractions by multiplying both sides of the inequality by 40:

40(a - 2/3) ≤ 16a ± 24 ± 25

Expanding:

40a - 80/3 ≤ 16a ± 24 ± 25

Now, let's simplify the expression on the left side:

40a - 80/3 = (120a - 80)/3

The inequality becomes:

(120a - 80)/3 ≤ 16a ± 24 ± 25

To eliminate the fraction, we can multiply both sides of the inequality by 3:

3(120a - 80)/3 ≤ 3(16a ± 24 ± 25)

Simplifying:

120a - 80 ≤ 48a ± 72 ± 75

Now, let's combine like terms:

120a - 80 ≤ 48a ± 147

Next, let's isolate the variable by moving the terms containing 'a' to one side:

120a - 48a ≤ 147 + 80

72a ≤ 227

Finally, divide both sides by 72 to solve for 'a':

a ≤ 227/72

The solution to the inequality is a ≤ 227/72.

User Mark Doliner
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