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Please help with this!

Please help with this!-example-1
User IqqmuT
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The equation of the line passing through the points (-4, 0) and (2, 2) in point-slope form is
y - 2 = (1)/(3)( x - 2 ).

The figure in the image is a graph of a linear function.

The equation of a line point-slope form is expressed as:

y - y₁ = m( x + x₁ )

Where x₁ and y₁ are the coordinates of a point and m is the slope.

From the graph, the passes through the points (-4, 0) and (2, 2).

First, we determine the slope (m):

Slope (m) = ( change in y ) / ( change in x )

Slope (m) = ( y₂ - y₁ ) / ( x₂ - x₁ )

Slope (m) = ( 2 - 0 ) / ( 2 - (-4) )

Slope (m) = ( 2 - 0 ) / ( 2 + 4 )

Slope (m) = 2 / 6

Slope (m) = 1/3

Now, plug the slope m = 1/3 and point (2,2) into the point-slope form:

y - y₁ = m( x + x₁ )


y - 2 = (1)/(3)( x - 2 )

Therefore, the equation of the line is
y - 2 = (1)/(3)( x - 2 ).

User Newguy
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