Question

Aluminum oxide (Al2O3) is a material used in the manufacturing of many ceramics by the reaction

below. If 3.50 moles of aluminum is reacted with 5.00 moles of oxygen gas, what mass of Al2O3, in
grams, can be produced by this reaction?
4Al (s) + 3O2 (g)  2Al2O3 (s)

Answer 1

To find the mass of Al2O3 produced, determine the moles of Al2O3 using the mole ratio. Then, multiply the moles of Al2O3 by its molar mass to find the mass in grams. In this case, 178.43 grams of Al2O3 can be produced.

Step-by-step explanation:

To determine the mass of Al2O3 produced, we need to calculate the moles of aluminum oxide first.

From the balanced chemical equation, we can see that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3. Therefore, the mole ratio between Al2O3 and Al is 2:4.

Given that 3.50 moles of Al is reacted, we can set up a proportion:

(2 mol Al2O3 / 4 mol Al) = (x mol Al2O3 / 3.50 mol Al)

Solving for x, we find that x is equal to 1.75 moles of Al2O3.

To calculate the mass of Al2O3, we use the molar mass of Al2O3, which is 101.96 g/mol.

Mass of Al2O3 = (1.75 mol Al2O3) * (101.96 g/mol)

= 178.43 g