To predict the two classes with the maximum and minimum possible number of players, use a dictionary to store the count of players for each class. Loop through the array of weights, determine the class for each weight, and increment the count for that class in the dictionary. Finally, find the classes with maximum and minimum counts and display the results.
To predict the two classes with the maximum and minimum possible number of players, we need to count the number of players in each class using the given initial weights. We can use a dictionary to store the count of players for each class. Loop through the array of weights, determine the class for each weight, and increment the count for that class in the dictionary. Finally, find the classes with maximum and minimum counts and display the results.
Python code:
weights = ['A', 'C', 'B', 'C', 'D', 'D', 'A', 'B', 'B', 'D']
count = {'A': 0, 'B': 0, 'C': 0, 'D': 0, 'F': 0}
for weight in weights:
if weight == 'A' or weight == 'B':
count['A'] += 1
elif weight == 'C' or weight == 'D':
count['C'] += 1
elif weight == 'F':
count['F'] += 1
max_class = max(count, key=count.get)
min_class = min(count, key=count.get)
print(f'The maximum number of players may exist in Class {max_class} with {count[max_class]} players')
print(f'The minimum number of players may exist in Class {min_class} with {count[min_class]} players')