Final answer:
To find the number of atoms of oxygen in 160 grams of N2O3, calculate the moles of N2O3 and then multiply by the number of oxygen atoms per molecule, resulting in approximately 3.80 x 10^24 oxygen atoms.
Step-by-step explanation:
The question concerns the number of atoms of oxygen in a certain mass of N2O3. To find this, first, we need to calculate the molar mass of N2O3, which is obtained from the atomic masses of nitrogen (N) and oxygen (O). Nitrogen has a molar mass of 14 g/mol, and oxygen has a molar mass of 16 g/mol. Therefore, the molar mass of N2O3 is (2 x 14) + (3 x 16) = 76 g/mol.
To find out how many moles 160 grams of N2O3 is, we divide the mass by the molar mass, which gives us 160 g / 76 g/mol ≈ 2.105 moles of N2O3.
Since each mole of N2O3 contains 3 moles of oxygen atoms, we multiply the number of moles of N2O3 by 3 to find the moles of oxygen atoms, which is 2.105 x 3 ≈ 6.315 moles of oxygen atoms.
Finally, to find the total number of oxygen atoms, we multiply the moles of oxygen by Avogadro's number (approximately 6.022 x 1023 atoms/mol), giving us 6.315 moles x 6.022 x 1023 atoms/mol ≈ 3.80 x 1024 oxygen atoms.