Final answer:
To treat 5,000 liters of latex with a 0.01% concentration of sodium sulphite, approximately 1515.15 mL or 1.515 liters of a 3.3% (w/w) stock solution is needed, assuming the density of the stock solution is similar to water.
Step-by-step explanation:
To calculate the volume of a stock solution containing 3.3% (w/w) sodium sulphite required to treat 5,000 liters of latex with a 0.01% (w/v) concentration, we use the dilution formula:
C1V1 = C2V2
where:
- C1 is the concentration of the stock solution (3.3% w/w)
- V1 is the volume of the stock solution required
- C2 is the desired concentration in the final solution (0.01% w/v)
- V2 is the volume of the final solution (5,000 liters)
Since the stock solution concentration is given as a weight/weight percentage and our final concentration is given as a weight/volume percentage, there is a need to convert our stock solution concentration (C1) into a weight/volume percentage by assuming the density of the stock solution is similar to water (1 g/mL). We do this because 1% (w/v) is equal to 1 g in 100 mL of solution. Thus:
3.3% (w/w) = 33 g in 1000 g of solution
For 1000 mL (equivalent to 1000 g since we are assuming the density is similar to water) of the stock solution:
3.3% (w/w) = 3.3% (w/v) = 33 g/1000 mL
Now we can solve for V1 using the dilution equation:
V1 = (C2 × V2) / C1
V1 = (0.01% × 5,000,000 mL) / 3.3%
V1 = (50 × 10³ mL) / 3.3%
V1 = 50,000 mL / 0.033
V1 = 1515151.51515152 mL approx
Therefore, approximately 1515.15 mL (or 1.515 liters) of the 3.3% (w/w) sodium sulphite stock solution is required to treat 5,000 liters of field latex.