Answer:
This question is incomplete, the complete part of the question is as follows:
1. Father’s phenotype _______ Father’s genotype ______
2. Mother’s phenotype ________ Mother’s genotype _______
3. What is the probability of this couple having a child who is a tongue roller?
- Father's phenotype is NON-ROLLER, while his genotype is rr.
- Mother's phenotype is ROLLER while her genotype is Rr
- The probability of this couple having a child who is a tongue roller is 50% or 1/2.
Step-by-step explanation:
This question involves a single gene coding for the ability or not to roll the to tongue in humans. The alelle for tongue roller (R) is dominant over the allele for non-roller (r). This means an heterozygote individual (Rr) will be able a tongue roller.
According to this question, a man who is a non-roller (rr) marries a woman who is heterozygous for tongue rolling (Rr) i.e. rr × Rr. The following gametes will be produced by each parent:
rr - r and r
Rr - R and r
Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
Rr, Rr, rr and rr
- Offsprings with genotype Rr (1/2 or 50%) will be tongue rollers
- Offsprings with genotype rr (1/2 or 50%) will be non-tongue rollers.
Hence, based on this question;
- Father's phenotype is NON-ROLLER, while his genotype is rr.
- Mother's phenotype is ROLLER while her genotype is Rr
- The probability of this couple having a child who is a tongue roller is 50% or 1/2