Final answer:
The molarity of the mixture of two solutions (one 4M and 10L, the other 2M and 40L) is calculated to be 2.4M by adding the total moles of solute from both solutions and dividing by the total volume of the mixture.
Step-by-step explanation:
To calculate the molarity of the mixture of two solutions, we can use the formula M1 x V1 + M2 x V2 = Mf x Vf, where M1 and M2 are the molarities of the solutions, V1 and V2 are the volumes of the solutions, Mf is the final molarity and Vf is the final volume of the mixture.
First, we must find the total number of moles of solute in each solution by multiplying the molarity by the volume:
Moles of solute in first solution = 4M x 10L
= 40 moles
Moles of solute in second solution = 2M x 40L
= 80 moles
Next, we add the moles of solute from both solutions to get the total moles of solute in the mixture:
Total moles of solute = 40 moles + 80 moles
= 120 moles
Then, we add the volumes of both solutions to get the total volume of the mixture:
Total volume = 10L + 40L = 50L
To find the final molarity (Mf), we divide the total moles of solute by the total volume of the mixture:
Mf = Total moles of solute / Total volume = 120 moles / 50L
= 2.4M
Therefore, the molarity of the mixture is 2.4M.