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A line of best fit was drawn to the plotted points in a data set below. Based on the line of best fit, for what x-value does y=13

User Sajattack
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The x-value corresponding to y=13 on the line of best fit, derived from points (0,5) and (10,11) with a slope of 0.6 and y-intercept of 5, is approximately 13.33.

Two points on the line of best fit: (0,5) and (10,11).

Slope of the line of best fit: 0.6.

Y-intercept of the line of best fit: 5.

The task is to find the x-value corresponding to y=13 on the line of best fit.

Finding the Slope (m):

The slope (m) is determined using the formula: "m equals the change in y divided by the change in x," where (x1, y1) and (x2, y2) are the coordinates of the two points.

Using the points (0,5) and (10,11): Slope (m) = (11 - 5) / (10 - 0) = 6 / 10 = 0.6.

Finding the Y-intercept (b):

The equation of a line in slope-intercept form is "y equals mx plus b."

We can use one of the points (let's use (0,5)) to find the y-intercept:

Plug in x = 0 and y = 5 into the equation: 5 = 0.6 * 0 + b.

Solving for b, we get b = 5.

Equation of the Line of Best Fit:

With the slope (m) and y-intercept (b), the equation of the line of best fit is y = 0.6x + 5.

Finding the X-value for y=13:

Plug in y = 13 into the equation and solve for x:

13 = 0.6x + 5.

Subtract 5 from both sides: 8 = 0.6x.

Divide by 0.6: x = 8 / 0.6 = 13.33.

Therefore, the x-value that corresponds to y=13 on the line of best fit is approximately 13.33.

A line of best fit was drawn to the plotted points in a data set below. Based on the-example-1
User Bejmax
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