It takes about 92.97 minutes for the ISS to complete one orbit.
To find the time it takes for the ISS to orbit the Earth, we can use Kepler's Third Law.
Kepler's Third Law states that the square of the orbital period is equal to the cube of the semi-major axis of the orbit.
The semi-major axis of the orbit is the average distance between the ISS and the center of the Earth, which is equal to the sum of the radius of the Earth and the height of the orbit above the Earth's surface.
In this case, the semi-major axis is 6400 km + 400 km = 6800 km.
Using Kepler's Third Law equation, T^2 = (4π^2/GM) * a^3, where T is the orbital period, G is the gravitational constant, M is the mass of the Earth, and a is the semi-major axis of the orbit, we can solve for T.
Plugging in the values, we get T^2 = (4π^2/6.67430 × 10^-11) * (6800 km)^3. Solving for T, we find that it takes approximately 5578.3 seconds for the ISS to complete one orbit.
Converting this to minutes, we get approximately 92.97 minutes. Therefore, it takes about 92.97 minutes for the ISS to orbit the Earth.
The probable question may be:
7.The ISS (International Space Station) orbits the Earth at about 400 km above the Earth's surface. The radius of Earth is about 6400 km. Use Kepler's 3rd Law and your Kepler's Constant for Earth to find and show how long it takes for the ISS to orbit the Earth in minutes: