Final answer:
From 6.02 x 10^23 particles of Calcium Hydroxide, which is 1 mole, we will get 2 moles of NH₃. With the molar mass of NH₃ being 17.03 g/mol, this means that 34.06 grams of ammonia will be produced.
Step-by-step explanation:
To determine how many grams of ammonia will be produced from 6.02 x 10^23 particles of Calcium Hydroxide, we must recognize that 6.02 x 10^23 particles is equivalent to 1 mole. The balanced chemical reaction for producing ammonia that involves calcium hydroxide has not been provided, but typical reactions involving calcium hydroxide that yield ammonia might follow an equation like:
(NH₂)₂SO₄ + Ca(OH)₂ → 2 NH₃ + CaSO₄ + 2 H₂O
Based on the stoichiometry of the reaction, we can see that 1 mole of Ca(OH)₂ produces 2 moles of NH₃. Therefore, from 1 mole of Ca(OH)₂, we will get 2 moles of NH₃. The molar mass of NH₃ (ammonia) is 17.03 g/mol. Thus, 2 moles of NH₃ corresponds to:
2 moles * 17.03 g/mol = 34.06 grams of ammonia.