The distance PR across the river is approximately 144 feet.
To find the distance PR across the river, we can use the law of sines in right triangle POC.
The law of sines states:
![\[(\sin A)/(a) = (\sin B)/(b) = (\sin C)/(c)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/94zylnuz4pu2b6sckj229hu45ghhfdyv9t.png)
In triangle POC:
![\[(\sin(\angle POC))/(OP) = (\sin(\angle OCP))/(OC)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/u958ftb6khzz1e4kfnsrz14pcbgeork7sd.png)
Given that
is a right angle,
, and we can rewrite the equation as:
![\[(1)/(OP) = (\sin(\angle OCP))/(OC)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/o6625o99zi5rvzrhe2veybelqjkk72fmib.png)
Now, substitute the known values:
![\[(1)/(OP) = ((RE)/(RO))/(OC)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9p4w7rgehstcz8xm1lve2swx8lkbux2m65.png)
![\[(1)/(OP) = ((255)/(115))/(320)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ljkgfrwkzedo0h6l9ab0zowi3f9iub3m48.png)
Now, solve for OP:
![\[OP = (320 * 115)/(255)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/bbk8nl45jjhkv2g419zw524kxz3jlrd6k0.png)
![\[OP \approx 144 \text{ ft}\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kuw9plvybqdw8n2yv4bls9ujgdufi0maa4.png)
So, the distance PR across the river is approximately 144 feet.