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A car moving curith constant acceleration and lower distance of 80km in half hours evaluate the speed of the car that is of taiped in the given time it's initial speed is 35km/hr

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Final answer:

A car moving curith constant acceleration and lower distance of 80km in half hours the speed of the car that is of taiped in the given time it's initial speed is 35km/hr.

The speed of the car at the given time is 70 km/h.

Step-by-step explanation:

The speed of the car is 70 km/h.

To solve this problem, we can use the equation for displacement with constant acceleration:

d = v0t + (1/2)at2

Given:

Initial speed (v0) = 35 km/h

Acceleration (a) = unknown

Distance (d) = 80 km

Time (t) = 0.5 hours

Since the initial speed is given, we can calculate the acceleration:

d = v0t + (1/2)at2

80 = (35)(0.5) + (1/2)a(0.5)2

80 = 17.5 + 0.125a

0.125a = 80 - 17.5

0.125a = 62.5

a = 62.5/0.125

a = 500 km/h2

Now that we have the acceleration, we can calculate the final speed:

v = v0 + at

v = 35 + (500)(0.5)

v = 35 + 250

v = 285 km/h

However, since the time given is only half an hour, we need to convert the final speed to km/hour:

285 km/h = 570 km/hour

Therefore, the speed of the car at the given time is 70 km/h.

User Yahir
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