The total resistance of two 2Ω resistors connected in series is B. 4Ω. Therefore, B. 4Ω is correct .
When resistors are connected in series, their resistances add up. In this case, you have two 2Ω resistors connected in series.
The total resistance (RT) in a series circuit is the sum of the individual resistances (R1 and R2):
RT=R1+R2.
For two 2Ω resistors in series:
RT=2Ω+2Ω=4Ω.
Therefore, the correct answer is:
B. 4Ω.
When resistors are in series, you simply add their resistance values to find the total resistance.
This is because the current has to flow through each resistor, and the total voltage drop across the resistors is the sum of the voltage drops across each resistor.
In mathematical terms, the total resistance in a series circuit is the algebraic sum of the individual resistances.
In this specific case, adding the resistances of the two 2Ω resistors results in a total resistance of 4Ω.