Question

Find all values of m for which the equation has one real solution.

4q²=9q−(m+2)

Write your answer starting with m, followed by an equals sign or inequality symbol (for example, m<5 ). Reduce all fractions.

Answer 1

4q² - 9q + (m + 2) = 0

(-9)² - 4(4)(m + 2) = 0

81 - 16(m + 2) = 0

81 - 16m - 32 = 0

49 - 16m = 0

16m = 49

m = 49/16 = 3 1/16