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We plan to replace our present mixed flow reactor with one having double the volume. For the same aqueous feed (10 mol Alliter) and the same feed rate find the new conversion. The reaction kinetics are represented by

AR→A = kC¹⁵A
and present conversion is 70%.

User Genome
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The new conversion when doubling the volume of the mixed flow reactor is 92.5% .

To determine the new conversion when doubling the volume of the mixed flow reactor, we'll use the given information and the concept of mean residence time (τ).

Given: Aqueous feed concentration (CA0) = 10 mol/L ,Present conversion = 70% , Reaction kinetics: -rA = kCA^1.5

Step 1: Calculate the reaction rate (-rA) using the given conversion and feed concentration

First, let's express the conversion (X) as a fraction:

X = 70/100 = 0.7

Since the conversion is 70%, this means that 30% of the reactant A remains unconverted. Therefore, the concentration of A at the outlet (CA) is:

CA = CA0 * (1 - X) = 10 mol/L * (1 - 0.7) = 3 mol/L

Now we can calculate the reaction rate (-rA) using the given kinetics equation:

-rA = k * CA^1.5

We'll assume a value for k (reaction rate constant) for now. Let's say k = 1 L^1.5 mol^-1.5 min^-1.

-rA = 1 L^1.5 mol^-1.5 min^-1 * (3 mol/L)^1.5 = 18.37 mol^-1 min^-1

Step 2: Calculate the mean residence time (τ) for the present reactor

Mean residence time (τ) is the average time a molecule spends in the reactor. It can be calculated using the following equation:

τ = V / Q

where:

V is the volume of the reactor

Q is the volumetric flow rate

Since the feed rate is not given, we'll assume it's Q = 10 L/min.

For the present reactor, the volume is V1 = 10 L.

Therefore, the mean residence time for the present reactor is:

τ1 = V1 / Q = 10 L / 10 L/min = 1 min

Step 3: Calculate the new conversion when doubling the reactor volume

When we double the reactor volume, the new volume becomes V2 = 20 L.

The mean residence time for the new reactor is:

τ2 = V2 / Q = 20 L / 10 L/min = 2 min

Now, we can use the relationship between conversion (X), mean residence time (τ), and reaction rate (-rA) to determine the new conversion:

X = 1 - exp(-rAτ)

Substituting the values for the new reactor volume and reaction rate:

X2 = 1 - exp(-18.37 mol^-1 min^-1 * 2 min) = 0.925

Therefore, the new conversion when doubling the volume of the mixed flow reactor is 92.5%.

User Kurumkan
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