Final answer:
The given Scheme code evaluates to the value 22.
Step-by-step explanation:
The given Scheme code is ((lambda (x)((lambda (x y)(+ x y))4 (* 6 x)))3).
To determine the value to be passed to the parameter y, we need to evaluate the expression inside the inner lambda in sequential order.
First, substitute x with the value 3 and calculate (* 6 3), which equals 18.
Then, substitute the result, 18, as the value for x in the outer lambda.
Finally, calculate (+ 4 18), which gives the final result of 22.