Question

A 509g mass oscillates with an amplitude of 13.0cm on a spring whose spring constant is 20.0N/m .

A. Determine the period T= ....... s

Answer 1

The period of the oscillation is approximately 1.0035 seconds.

Step-by-step explanation:

To determine the period (T) of the oscillation, we can use the formula

T = 2π√(m/k),

where m is the mass and k is the spring constant.

Given the mass of 509g (0.509kg) and the spring constant of 20.0N/m, we can substitute these values into the formula:

T = 2π√(0.509 / 20.0)

= 2π√(0.02545)

≈ 2π * 0.1595 ≈ 1.0035s

Therefore, the period T is approximately 1.0035 seconds.