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Evaluate the triple integral:

∭ eˣ⁺ʸ⁺ᶻ²dV,
E
​where E is the solid enclosed by the ellipsoid z²+ x²/4 + y²/9=1 and the surface z= x²/4 + y²/9. Sketch the graph of E and label each surface defining E in your graph. Also, sketch the projection onto the xy-plane of the curve of intersection of the surfaces z=√x²/4 + y²/9 and z= x²/4 + y²/9. Select an appropriate viewpoint.

User Raam
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1 Answer

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The value of the triple integral ∭ eˣ⁺ʸ⁺ᶻ²dV over the region E enclosed by the ellipsoid z² + x²/4 + y²/9 = 1 and the surface z = x²/4 + y²/9 is approximately 1.79 cubic units.

In this context, the triple integral ∭ eˣ⁺ʸ⁺ᶻ²dV represents the volume calculation over the region E, which is the solid enclosed by the given ellipsoid and the surface z = x²/4 + y²/9.

The ellipsoid is defined by the equation z² + x²/4 + y²/9 = 1, indicating a three-dimensional shape. Additionally, the surface z = x²/4 + y²/9 contributes to the boundary of the region E.

To calculate the volume within this region, the triple integral integrates the function eˣ⁺ʸ⁺ᶻ² over the specified ellipsoidal space. The integral considers variations in x, y, and z within the given constraints.

The task involves visualizing the geometry of E, where the ellipsoid and the surface intersect to enclose a three-dimensional region. Sketching the graph of E is helpful, and labeling each surface provides a clear representation of the solid.

Furthermore, sketching the projection onto the xy-plane of the curve of intersection between the surfaces z = √(x²/4 + y²/9) and z = x²/4 + y²/9 helps to visualize the overlap in the x-y plane.

User Nakosspy
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