Question

A student is observing an object of unknown mass that is oscillating horizontally at the end of an ideal spring. The student measures the object's period of oscillation with a stopwatch. Using a number of measurements, the student determines the following.

Spring content 85 N/m
Mass of object 0.50 kg
Amplitude of oscillation 0.30 m
maximum speed of object 3.9 m/s

The total energy of the object-spring system is most nearly
a. 0.98 J
b. 3.8 j
c. 7.6 J

Answer 1

The total energy of the object-spring system is nearly to the 3.8 J option b.

Step-by-step explanation:

The total energy of an object-spring system can be calculated using the formula:

E = (1/2)kA^2

where E is the energy, k is the spring constant, and A is the amplitude of oscillation.

In this case, the spring constant is 85 N/m, and the amplitude is 0.30 m. Plugging these values into the formula:

E = (1/2) * 85 N/m * (0.30 m)^2

Calculating this equation results in approximately 3.825 J, which is closest to option b. 3.8 J.