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A nurse is preparing to administer chlorpromazine 0.55 mg/kg PO to an adolescent who weighs 110 lb. Available is chlorpromazine syrup 10 mg/5 mL. How many mL should the nurse administer? (Round the answer to the nearest whole number)

User Mutahhir
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2 Answers

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13.75 = 14 mL

Convert 110 lb to kg: 110/2.2kg= 50kg X 0.55 mg/kg= 27.5 mg

Now use the formula Desired/Have × mL:

27.5 mg / 10mg × 5mL= 13.75 mL

User Ramdaz
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1 vote

Final answer:

The nurse should administer approximately 14 mL of chlorpromazine syrup to the adolescent.

Step-by-step explanation:

To calculate the amount of chlorpromazine syrup that the nurse should administer, we need to use the formula:

Dose (mg) = Weight (kg) x Dosage (mg/kg)

In this case, the weight of the adolescent is 110 lb and we need to convert it to kg. Since 1 lb is approximately 0.4536 kg, the weight of the adolescent in kg is 110 lb x 0.4536 kg/lb = 49.8952 kg (round to 49.9 kg).

Now, we can calculate the dose:

Dose (mg) = 49.9 kg x 0.55 mg/kg = 27.445 mg (round to 27 mg)

Next, we need to calculate the volume of the syrup to administer based on the concentration of the syrup.

The syrup has a concentration of 10 mg/5 mL, which means that for every 10 mg of chlorpromazine, there are 5 mL of syrup. Therefore, we can set up the following proportion:

10 mg / 5 mL = 27 mg / x mL

Cross-multiplying, we get:

10 mg * x mL = 5 mL * 27 mg

Simplifying, we find:

x = (5 mL * 27 mg) / 10 mg = 13.5 mL

Therefore, the nurse should administer approximately 14 mL of chlorpromazine syrup to the adolescent.

User Li Zheng
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