Question

Supply the missing value, if you varies jointly as x and z, then, y=kxz; x=y/kz; z=y/kxz?

y x z k equation
30 3 5 ____ _____
80 ____ 4 ___ y=2xz
____ 6 8 4 _____

Answer 1

In the joint variation equation y = kxz, where y varies jointly as x and z, the missing values are k = 2, x = 10, and z = 3/4 for the given sets of values. These values satisfy the joint variation relationship y = kxz.

The given relationship is y = kxz, indicating joint variation where y varies jointly as x and z, with k being the constant of variation.

For the first set of values, when x = 3 and z = 5, substituting into y = kxz gives 30 = k * 3 * 5. Solving for k, we get k = 2.

Now, with k = 2, using this constant in the other expressions:

For the second set of values, when y = 80 and z = 4, we have 80 = 2 * x * 4. Solving for x, we find x = 10.

For the third set of values, when y = 6 and x = 8, we have 6 = 2 * 8 * z. Solving for z, we find z = 3/4.

So, the missing values in the table are k = 2, x = 10, and z = 3/4.