Final answer:
Four point charges each have a charge of +2.0 μC and are situated at the corners of a square of side length 15 cm.
The magnitude of the force on one of the point charges is approximately 576 N.
Step-by-step explanation:
To find the magnitude of the force on one of the point charges, we need to calculate the electric force between the charges.
The electric force between two point charges is given by Coulomb's law:
F = k * (q1 * q2) / r^2
where F is the electric force, k is the electrostatic constant (9 × 10^9 N⋅m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
In this case, each charge is +2.0 μC, so we can calculate the force between one of the charges and the other three using Coulomb's law. Since the charges are located at the corners of a square, the distance between each pair of charges is 15 cm.
When we substitute the values into the equation, we get:
F = (9 × 10^9 N⋅m^2/C^2) * (2.0 μC * 2.0 μC) / (0.15 m)^2
Simplifying the equation, we find:
F = 576 N.
Therefore, the magnitude of the force on one of the point charges is approximately 576 N.