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If m∠ NPM=100 , what is m∠ TRM ?

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Angle addition postulate applied to triangle NSMP: m∠MSP = 40° (sum of angles in a triangle is 180°).

Based on the information given in the image and your question, we can see that we're dealing with a triangle formed by lines NS, SM, and PA. We're also given that m∠NSM = 100° and m∠SPA = 40° (the angle opposite to side PA is supplementary to the angle opposite to side SA).

We can use the angle addition postulate to solve for m∠MSP. This postulate states that the sum of the angles in a triangle is equal to 180°. So, we can write the equation:

m∠NSM + m∠MSP + m∠SPA = 180°

Substituting the values we know:

100° + m∠MSP + 40° = 180°

Combining like terms:

m/MSP + 140° = 180°

Subtracting 140° from both sides:

m∠MSP = 180° - 140°

Therefore, m∠MSP = 40°.

In short, the angle m∠MSP is 40° because it's the difference between the sum of the other two angles in the triangle (180°) and the values of those two angles (100° and 40°).

If m∠ NPM=100 , what is m∠ TRM ?-example-1
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