110k views
0 votes
What is the magnitude of the acceleration of the 40-kg block?

A) 0.5 ms²
B) 1.4 ms²
C) 1.75 ms²
D) 4.5 ms²
E) 5 ms²

User Hoh
by
7.5k points

1 Answer

5 votes

Final answer:

Using Newton's second law of motion .The magnitude of the acceleration of the 40-kg block is 0.025 m/s².

Step-by-step explanation:

The magnitude of the acceleration of the 40-kg block can be determined using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.

In this case, the force is unknown, but we can use the information given in question 10 as a reference. It states that a 5-kg object requires a force of 1 Newton to accelerate at 20 m/s².

So, we can calculate the force required to accelerate the 40-kg block using the same formula:

Force = mass * acceleration

Force = 40 kg * acceleration

Since we know the force required is 1 Newton, we can solve for the acceleration:

1 N = 40 kg * acceleration

acceleration = 1 N / 40 kg

acceleration = 0.025 m/s²

Therefore, the correct answer is not one of the options provided.

The magnitude of the acceleration of the 40-kg block is 0.025 m/s².

User Sion
by
7.8k points