Let a curve y = y (x) be given by the solution of differential equation cos(1/2cos⁻¹(e⁻ˣ))dx=√e²ˣ−1dy If it intersects y – axis at y = –1, and the intersection point point of the curve with x – axis is (α,0), then eα is equal to

Let's solve the given differential equation and find the curve
y=y(x).
The differential equation is given by:

To solve this, we'll separate variables and integrate:

Let's denote

cos(2u)=2
(u)−1 and sin(2u)=2sin(u)cos(u). The equation becomes:






Now, we can integrate both sides:


Now, substitute back



Now, let's solve for y(x). The curve intersects the y-axis at y = −1, which means when x=0:


This implies that the constant of integration is 1. So, the curve is given by:

Now, to find
, where (α,0) is the intersection point with the x-axis, substitute y=0


So,

Question:-
Let a curve y = y (x) be given by the solution of differential equation cos(1/2cos⁻¹(e⁻ˣ))dx=√e²ˣ−1dy If it intersects y – axis at y = –1, and the intersection point point of the curve with x – axis is (α,o), then eα is equal to __________.