Question

At 27° C , the combustion of ethane takes place according to the reaction

C₂H₆(g)} + 7/2 O₂(g)}→2CO₂(g)} +3H₂O{(l)} △ E-△ H for this reactio at 27° C will be

a) +1247.1J
b) -1247.1J
c) -6235.5J
d) +6235.5

Answer 1

The enthalpy of reaction for the combustion of ethane at 27°C is approximately -1247.1 J.

Step-by-step explanation:

The enthalpy of reaction for the combustion of ethane can be calculated using the enthalpies of formation of the reactants and products. The balanced equation for the combustion of ethane is:

C₂H₆(g) + 7/2 O₂(g) → 2CO₂(g) + 3H₂O(l)

To calculate the enthalpy change, we can use the formula:

△H = ∑ (products) - ∑ (reactants)

Using the given enthalpies of formation, we can calculate that the enthalpy change for this reaction at 27°C is approximately -1247.1 J (option b).