There are 2160 ways to form an eight-digit number with the given conditions.
The digits from 1 to 9 without repetition, if the first four places of the numbers are in increasing order and the last four places are in decreasing order:
First, we can fix the digit in the middle place. There are 9 choices for this digit.
Next, we can fill in the first three places. There are 8 choices for the first digit, 7 choices for the second digit, and 6 choices for the third digit.
Finally, we can fill in the last three places. There are 6 choices for the first digit, 5 choices for the second digit, and 4 choices for the third digit.
Therefore, the total number of ways to form an eight-digit number with the given conditions is 9 * 8 * 7 * 6 * 6 * 5 * 4 = 151200.
Dividing this number by 70, we get 2160.
Therefore, the answer is 2160.
Question:-
Number of ways in which eight digit number can be formed using the digits from 1 to 9 without repetition, if first four places of the numbers are in increasing order and last 4 places are in decreasing order , is 'n' then n / 70 is equal to.