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Prove that the tangent drawn at the mid-point of an arc of a circle is parallel to the chord joining the end points of the arc.

User Owl
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The tangent drawn at the midpoint of an arc AMB is parallel to chord AB. This follows from equal opposite angles, ensuring AB is parallel to the tangent TMT'

1. Given:

- Arc AMB with midpoint M.

- Tangent TMT' to the circle.

- Joining lines AB and MB.

2. Claim:

-
\( \text{Arc } AM = \text{Arc } MB \).

3. Proof of Claim:

- Since
\( \text{Arc } AM = \text{Arc } MB \), then
\( \angle MAB = \angle MBA \) (Equal sides corresponding to equal angles) ....(i).

4. Assertion:

-
\angle AMT =
\angle MBA.

5. Proof of Assertion:

- Since TMT' is a tangent,
\angle AMT =
\angle MBA (Angles in alternate segments are equal).

- From equation (i),
\angle AMT =
\angle MAB.

- Therefore,
\angle AMT =
\angle MAB =
\angle MBA.

6. Conclusion:

- AB is parallel to TMT' (Alternate angles are equal).

Hence, the tangent drawn at the midpoint of an arc of a circle is parallel to the chord joining the endpoints of the arc.

Prove that the tangent drawn at the mid-point of an arc of a circle is parallel to-example-1
User Nappstir
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