The distance of the first bright diffraction fringe from the strong central maximum is 0.002 meters.
To determine the distance of the first bright diffraction fringe from the strong central maximum, we can use the formula for the angular position of the nth order maximum in a single-slit diffraction pattern:
Part A:
The distance of the first bright diffraction fringe from the strong central maximum is given by:
y = (λL) / (2a)
where:
λ is the wavelength of the light (620 nm = 6.20 x 10^-7 m)
L is the distance between the slit and the screen (12.0 m)
a is the width of the slit (3.90 x 10^-3 mm = 3.90 x 10^-6 m)
Plugging in the values, we get:
y = (6.20 x 10^-7 m)(12.0 m) / (2)(3.90 x 10^-6 m) = 0.0020 m
Therefore, the distance of the first bright diffraction fringe from the strong central maximum is 0.002 meters.
Question
Light of wavelength 620 nm falls on a slit that is 3.90x10-3 mm wide. Part A How far the first bright diffraction fringe is from the strong central maximum if the screen is 12,0 m away Express your answer to three significant figures and include the appropriate units. HÅR O ? 1 = Value Units.