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For the system described by the transfer function below, H(s), find the differential equation relating the output y(t) to the input x(t) assuming that the systems are controllable and observable.

H(s)= [s² + 3s +5] / [s² + 8s² + 5s + 7]

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The differential equation relating the output y(t) to the input x(t) is (dy/dt) - 8y = 0. This can be obtained by converting the transfer function to a polynomial equation, setting the denominator to zero, and writing the corresponding differential equations.

Convert the transfer function to a polynomial equation:

Multiply both sides of the equation by the denominator, D(s) = s² + 8s² + 5s + 7:

s² + 3s + 5 = (s² + 8s² + 5s + 7)y(t)

Set the denominator to zero and solve for s:

s² + 8s² + 5s + 7 = 0

Factor the polynomial:

(s + 7)(s + 1) = 0

Solve for the roots:

s = -7, -1

Write the characteristic equation:

(s + 7)(s + 1) = 0

Write the corresponding differential equations:

For each root, write a differential equation of the form:

(dy/dt) + p_i y = 0

For s = -7:

(dy/dt) - 7y = 0

For s = -1:

(dy/dt) - y = 0

Combine the differential equations:

Since the system is assumed to be controllable and observable, the complete differential equation can be obtained by combining the two differential equations:

(dy/dt) - 7y - y = 0

(dy/dt) - 8y = 0

Therefore, the differential equation relating the output y(t) to the input x(t) is:

(dy/dt) - 8y = 0

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