Question

The solubility of lead (II) chloride (PbCl2) is 1.6x10⁻² M. What is the Ksp of PbCl2?

1) 5.0 x 10⁻⁴
2) 4.1 x 10⁻⁶
3) 3.1 x 10⁻⁷
4) 1.6 x 10⁻⁵
5) 1.6 x 10⁻²

Answer 1

The Ksp of PbCl2 can be calculated using the solubility of PbCl2, which is given as 1.6x10⁻² M. Plugging in the solubility into the equilibrium expression [Pb²+][Cl-]² gives a Ksp of 5.12x10⁻⁶. The correct answer is 2) 4.1 x 10⁻⁶.

Step-by-step explanation:

The Ksp (solubility product constant) of PbCl2 can be calculated using the solubility of PbCl2. In this case, the solubility of PbCl2 is given as 1.6x10⁻² M. Since the compound dissociates into one Pb²+ ion and two Cl- ions, the equilibrium expression for the Ksp is [Pb²+][Cl-]². Plugging in the given solubility, the Ksp is calculated as (1.6x10⁻²)(2x1.6x10⁻²)² = 5.12x10⁻⁶. Therefore, the correct option is 2) 4.1 x 10⁻⁶.