Final answer:
To heat a 1.0 kg block of iron from 10ºC to 50ºC, one would need 18000 joules of heat. This is calculated using the formula q = mcΔT, where m is the mass in grams, c is the specific heat capacity, and ΔT is the change in temperature.
Step-by-step explanation:
The student has asked how much heat is needed to increase the temperature of a 1.0 kg block of iron from 10ºC to 50ºC. The specific heat (c) of iron is given as 0.45 J/g°C. To calculate the heat (q), use the formula q = mcΔT, where m is mass, c is the specific heat, and ΔT is the change in temperature. The mass of the iron block should be converted to grams (1.0 kg = 1000 g). The temperature change (ΔT) is 50ºC - 10ºC = 40ºC. Hence, the heat required is:
q = mcΔT = (1000 g)(0.45 J/g°C)(40°C) = 18000 J
Therefore, 18000 joules of heat is needed to raise the temperature of the block as specified.