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Answer:

Explanation:

(a)


\boxed{time=(distance)/(speed) }

Route A:


t=(800)/(x) \ days

Route B:


t=(800)/(x-5) \ days

Route C:


t=((800+100))/(x+5)


=(900)/(x+5) \ days

(b)


t_B-t_C=20


(800)/(x-5) -(900)/(x+5) =20


(800(x+5))/((x+5)(x-5)) -(900(x-5))/((x+5)(x-5)) =(20(x+5)(x-5))/((x+5)(x-5))


800(x+5) -900(x-5) =20(x+5)(x-5)


800x +4000-900x+4500=20x^(2) -500


20x^(2) +100x-9000=0


x^(2) +5x-450=0

(c)


\boxed{x=(-b\pm√(b^2-4ac) )/(2a) }


x=(-5\pm√(5^2-4(1)(-450)) )/(2(1))


=18.9\ days

(answer must be in positive numbers, so -23.9 days is not valid

User Trevor Karjanis
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