Final answer:
The energy stored in capacitor W18 is 5.38 mJ and the energy stored in capacitor W63 is 2.69 mJ when they are connected in series.
Step-by-step explanation:
To find the energy stored in each capacitor when they are connected in series, we can use the formula for the energy stored in a capacitor: W = (1/2)CV^2.
For capacitor W18 with capacitance of 8.4 µF and voltage of 36.0 V, the energy stored would be:
W18 = (1/2)(8.4 x 10^-6 F)(36.0 V)^2 = 5.38 mJ
For capacitor W63 with capacitance of 4.2 µF and voltage of 36.0 V, the energy stored would be:
W63 = (1/2)(4.2 x 10^-6 F)(36.0 V)^2 = 2.69 mJ