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Find the length of the parametric curve x=1 18t², y=6 12t³, 0≤t≤3.

User Boies Ioan
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1 Answer

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Final answer:

The length of the parametric curve can be found using the arc length formula for parametric curves.

Step-by-step explanation:

The length of the parametric curve x=1 18t², y=6 12t³ with 0≤t≤3 can be found using the arc length formula for parametric curves:

Length = ∫[a,b] √[dx/dt]² + [dy/dt]² dt

In this case, the length is:

Length = ∫[0,3] √[36t²] + [72t²] dt

Simplifying and evaluating the integral gives:

Length = ∫[0,3] √[108t²] dt

Length = 12 √3.

User Blixt
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