Final answer:
The zeros of the function h(x) = 2x² - 72 are x = 6 and x = -6.
Step-by-step explanation:
To find the zeros of the function h(x) = 2x² - 72, we set the function equal to zero and solve for x:
2x² - 72 = 0
Dividing both sides by 2 gives:
x² - 36 = 0
Next, we can factor the quadratic equation:
(x - 6)(x + 6) = 0
Setting each factor equal to zero and solving for x gives the zeros:
x - 6 = 0, x + 6 = 0
x = 6, x = -6