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For a sample of stomach acid that is 1.45×10-2 M in HCl, how many moles of HCl are in 19.6 mL of the stomach acid?

User Maggy
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Final answer:

To calculate the moles of HCl in 19.6 mL of stomach acid with a molarity of 1.45×10-2 M, you multiply the volume in liters (0.0196 L) by the molarity, resulting in 2.842×10-4 moles of HCl.

Step-by-step explanation:

The student is asking how to calculate the number of moles of HCl in a 19.6 mL sample of stomach acid with a molarity of 1.45×10-2 M. To find the moles of HCl, we use the formula: moles = molarity × volume in liters. First, convert 19.6 mL to liters by dividing by 1000: 19.6 mL × (1 L / 1000 mL) = 0.0196 L. Then, multiply the volume in liters by the molarity of the solution: 1.45×10-2 M × 0.0196 L = 2.842×10-4 moles of HCl.

User Dean Swiatek
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