Question

For the reaction c6h14(g) → c6h6(g) + 4h2(g), Δp(h2)/Δt was found to be 2.5 × 10–2 atm/s. Determine Δp(c6h14)/Δt for this reaction at the same time.

Answer 1

To find Δp(c6h14)/Δt for the reaction c6h14(g) → c6h6(g) + 4h2(g), divide the Δp(h2)/Δt (2.5 × 10–2 atm/s) by 4, yielding 6.25 × 10–3 atm/s.

Step-by-step explanation:

To determine the change in pressure over time (Δp(c6h14)/Δt) for the reaction c6h14(g) → c6h6(g) + 4h2(g), we must look at the stoichiometry of the reaction. The reaction shows that for each mole of c6h14 that reacts, 4 moles of h2 are produced. Therefore, the rate of change in pressure for h2 will be four times the rate of change in pressure for c6h14.

Since Δp(h2)/Δt was found to be 2.5 × 10–2 atm/s, we simply divide this value by 4 to get the Δp(c6h14)/Δt:

Δp(c6h14)/Δt = Δp(h2)/Δt / 4 = (2.5 × 10–2 atm/s) / 4 = 6.25 × 10–3 atm/s.

The change in pressure over time for c6h14 at the same time is 6.25 × 10–3 atm/s.