Question

A plant has dominant and recessive traits for flower color. The dominant color is amethyst (a), and the recessive trait is white (a). Which punnett square correctly shows two homozygous parents producing heterogeneous offspring?

1) a
2) b
3) c
4) d
5) e

Answer 1

A correct Punnett square showing two homozygous parents producing heterozygous offspring will have one parent with 'AA' genotype and another with 'aa' genotype. All offspring will have 'Aa' genotypes, indicating heterozygous dominant traits.

Step-by-step explanation:

The question asks about a Punnett square that shows two homozygous parents producing heterozygous offspring. The correct Punnett square would involve one parent with homozygous dominant alleles ('AA' for amethyst flower color) and the other parent with homozygous recessive alleles ('aa' for white flower color). When these are crossed, all the offspring would be heterozygous (Aa), displaying the dominant amethyst flower color but carrying the recessive white allele. Here's how the Punnett square would look:

| A | A |
| a | Aa | Aa |
| a | Aa | Aa |

In this example, the letters 'A' and 'a' represent the alleles for flower color, where 'A' is dominant (amethyst), and 'a' is recessive (white). Since each offspring receives one allele from each parent, all offspring will have the 'Aa' genotype, making them all heterozygous with amethyst flower color. The question cannot be answered with the options (1-5) provided since a description of the Punnett squares labeled as such is not given. In any correct Punnett square showing crossing of two homozygous parents with dominant and recessive traits, all offspring will be heterozygous.