Question

Suppose a solution was too concentrated for an accurate reading with the spectrophotometer. The concentrated solution was diluted by placing 1 ml of the concentrated solution in 4 ml of water. The molar concentration is 3.5x10⁻⁶. What is the original stock solution?

Answer 1

To find the original stock solution, use the dilution formula: C1V1 = C2V2. The volume of the stock solution can be calculated as (3.5x10⁻⁶ M x 5 ml) / 3.5x10⁻⁶ M, which gives a result of 5 ml.

Step-by-step explanation:

To find the original stock solution, we can use the dilution formula: C1V1 = C2V2. Here, C1 and V1 represent the concentration and volume of the stock solution, and C2 and V2 represent the concentration and volume of the diluted solution. We are given that C2 = 3.5x10⁻⁶ M and V2 = 5 ml. The volume of the stock solution can be calculated as follows:

C1 x V1 = C2 x V2
V1 = (C2 x V2) / C1
V1 = (3.5x10⁻⁶ M x 5 ml) / 3.5x10⁻⁶ M
V1 = 5 ml

Therefore, the original stock solution is 5 ml.