Question

What number times itself gives you -99 and adds to itself to give you 2?

1) -11
2) -9
3) 11
4) 9

Answer 1

The question is seeking a real number that squares to -99 and adds to itself to give 2, which is not possible based on the multiplication and addition rules. Hence, none of the provided options is correct.

Step-by-step explanation:

The question is looking for a number that when squared (multiplied by itself) gives -99 and when added to itself gives 2. In mathematical terms, we are looking for a number x such that x² = -99 and 2x = 2.

However, according to the rule that when two negative numbers multiply, the answer has a positive sign (e.g., (-4) x (-3) = 12), and when two positive numbers multiply, the answer also has a positive sign (e.g., 2x3 = 6), it's impossible for a real number multiplied by itself to result in a negative number like -99. Therefore, there is no real number that satisfies the condition x² = -99.

For the addition part, when a number is added to itself, the result is simply 2 times that number. So if 2x = 2, dividing both sides by 2 gives x = 1. But x = 1 does not satisfy the multiplication condition x² = -99.

Therefore, none of the options provided (-11, -9, 11, 9) can satisfy both conditions simultaneously, as the first condition involving x² = -99 has no solution in real numbers.