Final answer:
The force required to start a 50kg object in motion along a level surface when the coefficient of static friction is 0.3 is greater than 147 N, which is the maximum static frictional force.
Step-by-step explanation:
The force required to start a 50 kg object in motion along a level surface when the coefficient of static friction is 0.3 can be calculated using the equation for static friction, which is:
Fstatic = μs × N,
where:
- Fstatic is the maximum static frictional force,
- μs is the coefficient of static friction,
- N is the normal force exerted by the object onto the surface.
For an object on a level surface, the normal force N is equal to the weight of the object, which is calculated by multiplying the mass m of the object by acceleration due to gravity g (9.8 m/s²). Thus, N = m × g = 50 kg × 9.8 m/s² = 490 N.
The maximum force of static friction would therefore be:
Fstatic = 0.3 × 490 N = 147 N.
This means a force greater than 147 N is required to overcome the static friction and start the object moving.