160k views
3 votes
What is the magnitude of the charge if the electrical field strength is 2.8 x 10⁶ and the distance is 2.4 cm?

1 Answer

5 votes

Final answer:

The magnitude of the charge is approximately 3.79 x 10⁻¹³ Coulombs.

Step-by-step explanation:

To calculate the magnitude of the charge, we can use the equation E = kQ/r², where E is the electrical field strength, Q is the charge, and r is the distance. Rearranging the equation, we have Q = Er²/k.

Plugging in the given values, the magnitude of the charge can be calculated as follows:

Q = (2.8 x 10⁶) x (2.4 cm) x (2.4 cm) / (8.99 x 10^9 N m² / C²) = (2.8 x 10⁶) x (0.024 m) x (0.024 m) / (8.99 x 10^9 N m² / C²) = 3.79 x 10⁻¹³ C

Therefore, the magnitude of the charge is approximately 3.79 x 10⁻¹³ Coulombs.

User Johnny Utahh
by
8.5k points

No related questions found