Final answer:
The number of moles of H₂O formed in the combustion reaction of methanol is 19.6 moles.
Step-by-step explanation:
The balanced equation for the combustion of methanol is 2CH₃OH + 3O₂ → 2CO₂ + 4H₂O.
From the equation, we can see that for every 2 moles of methanol reacted, 4 moles of water are formed.
Therefore, to calculate the number of moles of H₂O formed when 9.8 moles of CH₃OH are reacted, we can set up a proportion:
2 moles CH₃OH / 4 moles H₂O = 9.8 moles CH₃OH / x moles H₂O
Solving for x:
x = 19.6 moles H₂O