Question

A coin is tossed 2n times. The chance that the number of times one gets head is not equal to the number of times one gets tail is

A (2n)!(n!)².(1/2)²n
B 1−(2n)!/(n!)²
C 1−(2n)!/(n!)².1/4n
D none of these

Answer 1

The correct answer is Option B. The chance that the number of times one gets a head is not equal to the number of times one gets a tail when a coin is tossed 2n times can be calculated using the formula 1−(2n)!/(n!)².

Step-by-step explanation:

The chance that the number of times one gets a head is not equal to the number of times one gets a tail when a coin is tossed 2n times can be calculated using the formula 1−(2n)!/(n!)². This formula represents the probability of getting a different number of heads and tails. Let's break down the steps:

1. Calculate the factorial of 2n: (2n)!
2. Calculate the factorial of n: (n!)
3. Square the factorial of n: (n!)²
4. Calculate 1−(2n)!/(n!)²

So, the correct answer is option B: 1−(2n)!/(n!)².