Question

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford. Let h represent the whole number of hours that the plumber works. How many hours of work can Anand afford?

Answer 1

Anand can afford at most 6 hours of plumbing work within his budget of $250, as the plumber charges an initial fee of $65 plus an hourly rate of $28.

Step-by-step explanation:

Anand can calculate the maximum number of hours of plumbing work he can afford by using a linear equation that includes both the initial fee and the hourly rate. The total cost (T) is equal to the initial fee plus the hourly rate (h) times the number of hours:

T = initial fee + (hourly rate \u00d7 h)

In Anand's case, we have an initial fee of $65 and an hourly rate of $28. The total amount Anand would like to spend is no more than $250. We set up an inequality to represent this:

65 + 28h \u2264 250

Now we solve for h:

28h \u2264 250 - 65

28h \u2264 185

h \u2264 185 / 28

h \u2264 6.607 (since h must be a whole number, we round down)

Anand can afford at most 6 hours of work from the plumber.