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An ideal gas has an initial volume of 2.55 L. At constant pressure, it is cooled to 22.00°C where its final volume is 1.75 L. What is the initial temperature?

User Dnatoli
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Final answer:

To find the initial temperature, we can use Charles's Law and the formula V1/T1 = V2/T2. Rearranging the formula, we find that the initial temperature is approximately -195.307 °C.

Step-by-step explanation:

To solve this problem, we can use Charles's Law, which states that the volume of an ideal gas is directly proportional to its temperature, assuming pressure and amount are kept constant.

Using the formula V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature, we can rearrange the formula to solve for the initial temperature:

T1 = (V1/T1) * T2 = (2.55 L / (22.00 °C + 273.15 K)) * (1.75 L / (5.72 °C + 273.15 K)) = -195.307 °C

Therefore, the initial temperature of the gas is approximately -195.307 °C.

User Dsolimano
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