Final answer:
The final temperature of the solution is 25.6°C.
Step-by-step explanation:
To calculate the final temperature of the solution, we can use the specific heat equation:
q = m * C * ΔT
where q is the heat flow, m is the mass of the solution, C is the specific heat capacity of the solution, and ΔT is the change in temperature.
In this case, the mass of the water is 126 g and its specific heat capacity is 4.18 J/°C·g. The mass of the solute (KOH) is 11.0 g. We can assume that the specific heat capacity of the solution is the same as that of water.
The change in temperature is calculated to be 11.7°C. Substituting the values into the equation, we get:
q = (11.0 g + 126 g) * 4.18 J/°C·g * 11.7°C
q = 17175 J
Assuming no heat loss to the surroundings, we can equate the heat lost by the KOH to the heat gained by the water:
q = -q
(11.0 g) * (-2.28 J/g) = (126 g) * (4.18 J/°C·g) * ΔT
Solving for ΔT, we find:
ΔT = -0.0481°C
The final temperature of the solution is:
25.6°C + (-0.0481°C) = 25.6°C